var rect = new Rectangle(x, y, SQUARE_SIZE, SQUARE_SIZE); rect.setColor(color); rect.setFilled(true); add(rect);

if (row % 2 == 0) // normal parity else // shifted: (col % 2 == 0) gives opposite

private static final int NUM_ROWS = 8; private static final int NUM_COLS = 8;

Instead of two colors, use four colors repeating. Use (row + col) % 4 to choose from an array of colors. Variation C: User Resizable Canvas In the graphics version, recompute square size on window resize. This is rare for CodeHS but possible in advanced sections. Testing Your Solution Before submitting, test these cases manually:

@.@.@ .@.@. @.@.@ .@.@. @.@.@ const readline = require('readline'); const rl = readline.createInterface( input: process.stdin, output: process.stdout ); rl.question("Rows: ", (rows) => rl.question("Cols: ", (cols) => rows = parseInt(rows); cols = parseInt(cols); for (let i = 0; i < rows; i++) let line = ""; for (let j = 0; j < cols; j++) if ((i + j) % 2 === 0) line += "X"; else line += "O";

System.out.print("Enter number of rows: "); int rows = input.nextInt(); System.out.print("Enter number of columns: "); int cols = input.nextInt(); for (int i = 0; i < rows; i++) for (int j = 0; j < cols; j++) if ((i + j) % 2 == 0) System.out.print("@"); else System.out.print("."); System.out.println(); // new line after each row

If row % 2 == 1 , start with the opposite color. Equivalent to: